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3 years ago

Which choice could be used in proving that the given triangles are similar?

Mathematics

1 answer:

Vadim26 [7]3 years ago

5 0

Answer: . To prove triangles are similar, you need to prove two pairs of corresponding angles are congruent

Step-by-step explanation:

SSS similarity postulate

The SSS similarity postulate says that if the lengths of the corresponding sides of two triangles are proportional then the triangles must be similar.

In the given figure , we have two triangles ΔABC and ΔXYZ such that the corresponding sides of both the triangles are proportional.

i.e.

Then by SSS-similarity criteria , we have

ΔABC ≈ ΔXYZ

BRAINLIEST PLEASE????

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Consider the sequence 130, 143, 156, 169, ... Write an explicit formula to represent the arithmetic sequence and use it to find

pantera1 [17]

<u>Answer:</u>

a(n) = 130 + (n-1) 13

13th term = 286

<u>Step-by-step explanation:</u>

We are given a sequence of numbers: 130, 143, 156, 169, ... and we are to write an explicit formula to represent the arithmetic sequence and use it to find the 13th term.

We know that the arithmetic sequence can be defined by:

$a_n=d(n-1)+c$

where $d$ = the common difference between consecutive terms ; and

$c$ = $a_1$

$a_{13}=130+(12)13 = 286$

Therefore, the formula for this sequence will be a(n) = 130 + (n-1) 13 and 13th term is 286.

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The sum of two numbers is 49. The sum of the smaller and 2 times the larger is 83. Find the two numbers.

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Let the small number be x and the big number be y
x+y=49
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3 years ago

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Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$