Which choice could be used in proving that the given triangles are similar?

Mathematics

1 answer:

Vadim26 [7]2 years ago

5 0

Answer: . To prove triangles are similar, you need to prove two pairs of corresponding angles are congruent

Step-by-step explanation:

SSS similarity postulate

The SSS similarity postulate says that if the lengths of the corresponding sides of two triangles are proportional then the triangles must be similar.

In the given figure , we have two triangles ΔABC and ΔXYZ such that the corresponding sides of both the triangles are proportional.

i.e.

Then by SSS-similarity criteria , we have

ΔABC ≈ ΔXYZ

BRAINLIEST PLEASE????

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Based on the Nielsen ratings, the local CBS affiliate claims its 10 p.m. newscast reaches 41% of the viewing audience in the are

damaskus [11]

Answer:

H0:p=0.41

Step-by-step explanation:

The null hypothesis always contain equality i.e. (=) sign. The null hypothesis contains the statement regarding population parameter. Here, the claim about population proportion is mentioned in the statement that 10 p.m. newscast of local CBS reaches 41% of viewers. So, the null hypothesis would be

Null hypothesis:H0: p=0.41.

4 0

2 years ago

#82 will give brainliest to best answer!

Fofino [41]

Answer:

$\frac{6}{k-6}$

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ ÷ $\frac{(k-6)^2}{k(k-6)}$ × $\frac{6(k-10)}{k(k + 6)}$ . We know that division is simply multiplication by the reciprocal, so that whole equation will turn into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ × $\frac{k(k-6)}{(k-6)^2}$ × $\frac{6(k-10)}{k(k+6)}$ . Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into $\frac{6}{k-6}$ which is our final answer, as it cannot be simplified further.