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mars1129 [50]
2 years ago
7

What is the value of the expression “-5(3+5)”

Mathematics
2 answers:
Snowcat [4.5K]2 years ago
8 0

-5 (3 + 5)

-5 (8)

-5 × 8

= -40

Good luck :)

velikii [3]2 years ago
8 0

Answer:

-40

Step-by-step explanation:

First you distribute

-5 · 3 = -15

-5 · 5 = -25

Then you add

-15 + (-25) = -40

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-2.7+17.8+29.5+8.9=?
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64.5

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64.5

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Use the point-slope formula to write an equation of the line that passes through (4,10) and has a slope of m= 3. Write the
baherus [9]
Answer:
3x --y -2= 0
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4 0
2 years ago
6у – 6 = 4у + 16<br> A.y=2.2<br> B. y= -2.2<br> C. у= 11<br> D. у= 5
Korvikt [17]

Answer:

C. y=11

Step-by-step explanation:

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7 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

0 = 4x^ 2 – 3x – 1

The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

b^2 - 4ac

The solution contains the term \sqrt{b^2 - 4ac} which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

For the quadratic equation 2x^2 - 7x - 9

b^2 - 4ac

= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121

This equation has two real number solutions.

For the quadratic equation 4x^ 2 - 3x- 1

b^2 - 4ac

= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

#SPJ1

5 0
2 years ago
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