There are 8 marbles in a bag, all of different colors. In how many orders can 4 marbles be chosen? In other words, what is the
2 answers:
I think the answer will be 70
I got 70
Combination=n!/((n-r)!r!)
=8!/((8-4)!*4!)
=8*7*6*5*4!/(4!*4!)
=8*7*6*5/(4*3*2)
=70 ways
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Step-by-step explanation:
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40
Step-by-step explanation:
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