Question

There are 8 marbles in a bag, all of different colors. In how many orders can 4 marbles be chosen? In other words, what is the

Answer 1

I think the answer will be 70

Answer 2

I got 70

Combination=n!/((n-r)!r!)

=8!/((8-4)!*4!)

=8*7*6*5*4!/(4!*4!)

=8*7*6*5/(4*3*2)

=70 ways