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lys-0071 [83]
3 years ago
13

Which is the best reason why step 1 is a good first step in the solution shown?

Mathematics
1 answer:
Savatey [412]3 years ago
5 0
Hope this helps! :) When you multiply by 5 on both sides, it cancels out the 5 on the left side!(of the equal sign). To undo division, you must use multiplication! On the left side, division is being used, so multiply it and it goes away(Or undos it)!

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4x − 1 < 11 solve for x
kvv77 [185]

Answer:

\huge \boxed{x < 3}

Step-by-step explanation:

4x - 1 < 11

Add 1 on both sides.

4x - 1 + 1 < 11 + 1

4x < 12

Divide both sides by 4.

(4x)/4 < 12/4

x < 3

8 0
3 years ago
3 times a certain number n is added to 6, the sum is 20 more than the original
Vikentia [17]

Answer:

n = 5.33→

Step-by-step explanation:

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What are the first five terms of the sequence defined by the given function?
kenny6666 [7]

Answer: B. -6, -4, -2, 0, 2

Step-by-step explanation: Use the attachment to help you with your answer.

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2 years ago
What is the domain of the given function?
andrezito [222]
I have no idea tbh bro
7 0
2 years ago
A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he
Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as R(x)=80x-0.2x^ 2 . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ R(x)=80x-0.2x^ 2

⇒ \frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}

⇒ \frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}

⇒ 0=80-2x(0.2)

⇒ \frac{80}{0.4}=x

⇒ x=200

Now , Value of function at x=200 is :

⇒ R(200)=80(200)-0.2(200)^ 2

⇒ R(200)=16000-8000

⇒ R(200)=8000

Therefore , The maximum units is 200 and , Total revenue is $8,000

7 0
2 years ago
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