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Illusion [34]
2 years ago
11

Find the length of the segment indicated , round your answer to the nearest 10th if necessary PLEASE help I really need it. Don'

t just do it for points pls

Mathematics
2 answers:
pentagon [3]2 years ago
7 0

Answer:

Hope It Help

Step-by-step explanation:

<em>Brainliest </em><em>please</em>

lubasha [3.4K]2 years ago
6 0

Answer:

hope it help

Step-by-step explanation:

brainlist please

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What are the solutions of the quadratic equation 4x^2-8x-12=0
Wewaii [24]

Answer:

<h3>          x₁ = -1,   x₂ = 3</h3>

Step-by-step explanation:

4x^2-8x-12=0\\{}\qquad\qquad^{\div4\qquad\div4}\\x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\\\\x+1=0\quad\vee\quad x-3=0\\\\x=-1\quad\vee\quad x=3

6 0
3 years ago
Which is the range of the following relation?
Afina-wow [57]

Answer:

Odd integers

Step-by-step explanation:

The range is odd integers, if you add 1 to any even integer it becomes an odd integer. 2+1=3; 10+1=11

6 0
3 years ago
Solve for (4x+6)+(-x+2) please i need help
postnew [5]

Answer:

3x - 8

Step-by-step explanation:

Step 1:

( 4x + 6 ) + ( - x + 2 )

Step 2:

4x - 6 + - x - 2

Step 3:

3x - 6 - 2

Answer:

3x - 8

Hope This Helps :)

8 0
4 years ago
Read 2 more answers
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
Find the derivative of f(x) = 2x^2 - 4x +3
ivolga24 [154]

Explanation

2x^2-4x+3

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}

also, the derivate of a sum is the sum of the derivates

hence

\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}

Step 1

apply:

\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}

therefore, the answer is

8 0
1 year ago
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