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rewona [7]
3 years ago
11

Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.

Physics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

14.57 ohms

Explanation:

Here in the figure ,Rb & R₄are in series  & also  Rc & R₅ are in series. As they are in series , ( Rb + R₄ ) & (Rc & R₅) are in parallel . So the equivalent resistance in that branch = ( 2 + 18 ) ║ ( 3 + 12 )

                                          = 20 ║ 15

                                          = (20×15) / (20 + 15)

                                          = 8.57 ohms

Also Ra ( 6 ohm ) is in series with that branch ,. So the equivalent resistance of the whole circuit = 8.57 + 6 = 14.57 ohms.

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frosja888 [35]

Half a wavelength must fit exactly into the length of a vibrating cord

Explanation:

A standing wave is a wave produced by the interference between a wave and its reflection. A standing wave is the wave produced, for instance, in the string of a guitar.

A standing wave is different from other types of waves because it does not propagate in space, but it only vibrate in a fixed region.

A standing wave is characterized by the presence of:

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The two ends of the string do not vibrate: this means that they always correspond to two nodes. If we take the fundamental mode of vibration of the string (so, no other nodes), we see that the length of the string corresponds to the distance between two consecutive nodes: however, this also corresponds to half the wavelength of the wave. Therefore, we can conclude that the correct option is

Half a wavelength must fit exactly into the length of a vibrating cord

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3 years ago
A soccer ball kicked on a level field has an initial vertical velocity component of 15.0 mps. assuming the ball lands at the sam
telo118 [61]

Answer:

The time taken for the ball to fly up in the air and back down again is 3.058 seconds.

Explanation:

Since the ball ends up at the same vertical distance ( on the ground) as it was at the start of its motion, we can set the total displacement of the ball equal to 0.

Thus, this problem can be simply solved by the following equation of motion:

s = u*t + \frac{1}{2} (a*t^2)

Here, s = total change in distance = 0 m

u = initial speed = 15 m/s

a = acceleration due to gravity = -9.81 m/s^2

t = time (to be found)

Substituting these values in the equation we get:

0=15t+0.5(-9.81t^2)

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t=15/4.905

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So, the time taken for the ball to fly up in the air and back down again is 3.058 seconds.

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4 years ago
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tresset_1 [31]

Answer:

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Explanation:

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