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3 years ago

How do you put 63, 57, 52, 62, 60, 59, 55, 62, 61, 56 into a box plot?

Mathematics

2 answers:

Mariulka [41]3 years ago

7 0

456 yea that the answer because it is

Luda [366]3 years ago

5 0

Answer:

the answer is 456

Explanantion:

used math

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Randall had an AGI of $45,000. He had $1500 in medical expenses, paid $1356 in mortgage interest, and drove a company car for wo

ehidna [41]

Of the three mentioned items, Randall would not be able to claim his medical expenses on his itemized portion of his taxes because they would need to be at least 10% of his AGI.

10% of $45000 is $4500.

His mortgage interest is deductible.

The vehicle expenses (not reimbursed by the company) that he incurs from driving the company car would be deductible. This would only be the amount over 2% of the AGI.

So, anything over 2% of $45000 (over $900 in gas, etc.. not reimbursed by the company) would be deductible.

3 0

3 years ago

Read 2 more answers

25% of what number is 75

goldenfox [79]

Let's form an equation. To find the percent of a number, you multiply the percent divided by 100 and the initial number. X will be the initial number.
.25x=75; let's divide.
75÷0.25= 300
The initial number is 300. We can make sure 75 is a quarter of 300 by dividing 300 by 4.
300÷4=75

So, the number is 300.

5 0

4 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the critical points.

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

6 0

4 years ago

- (4x4- 2x' +7x²+2 x - 1)=(x+3)

Gnom [1K]

Answer:

No solution?

Step-by-step explanation:

Im confused, can you give more information.

4 0

4 years ago

Raoul bought 9 bags of granola mix. Each bag cost $5.59. How much did Raoul spend?

IRINA_888 [86]

Answer:

$50.31

Step-by-step explanation:

9x5.59=50.31

An easy way to do it is take out the decimals and multiply. Then add the decimals by seeing how many places in 5.59 (2) and move the decimal 2 times on your answer.

7 0

3 years ago