If you count by 5's, you have to count<br> times.

In a test of the effectiveness of garlic for lowering cholesterol, 4545 subjects were treated with garlic in a processed tablet

n200080 [17]

Answer:

$5.1 - 2.015 \frac{19.1}{\sqrt{45}}= -0.637$

$5.1 + 2.015 \frac{19.1}{\sqrt{45}}= 10.837$

And for this case since the confidence interval contains the value 0 we don't have significant evidence that we have a net change in the levels

Step-by-step explanation:

For this case we have the following info given:

$n=45$ represent the sample size

$\bar X= 5.1$ represent the sample mean

$s= 19.1$ represent the sample deviation

We can calculate the confidence interval for the mean with the following formula:

$\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}$

The confidence level is 0.90 then the significance level would be $\alpha=0.1$ and the degrees of freedom are given by:

$df= n-1 = 45-1=44$

And the critical value for this case would be:

$t_{\alpha/2}=2.015$

And replacing we got:

$5.1 - 2.015 \frac{19.1}{\sqrt{45}}= -0.637$

$5.1 + 2.015 \frac{19.1}{\sqrt{45}}= 10.837$

And for this case since the confidence interval contains the value 0 we don't have significant evidence that we have a net change or efectiveness in the levels

7 0

3 years ago

Which of the following is not a factor that may affect biodiversity?

Mandarinka [93]

B!!!!!!!!!!!!!!!!!!!!!!!!!

6 0

3 years ago

Read 2 more answers

Which is better: Car A that travels 308 miles on 11 gallons of gasoline OR Car B that travels 406 miles on 14 gallons of gasolin

Jet001 [13]

$\begin{gathered} \text{Car A travels 308 miles on 11 gallons, so, the ratio of miles per galon is} \\ \frac{308}{11}=28\text{ miles per gallon} \\ \\ \text{for the car B, the ratio is} \\ \frac{406}{14}=29\text{ miles per gallon} \end{gathered}$

thus, the best car is car B,because it can tavel 29 miles with only one gallon,andcar A can only travel 28 miles with one gallon.

5 0

1 year ago

Sara worked 24 hours last week. Joan worked for hours less than Sara, and Erin worked half as many hours as Joan. How many hours

Vaselesa [24]

Sara worked 1 day last week
Joan worked for 20 hours last week
And Erin worked for 10 hours last week

3 0

3 years ago

It takes me into 30 minutes to walk from home to school when walking at 5 km per hour What is her average cycling speed If it ta

GREYUIT [131]

Answer:

10 km/h

Step-by-step explanation:

I'm not really sure about this but no ones answering your question and I wanna help.

So basically to calculate the average speed you need to divide the distance travelled by time taken

But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km

Now that we have the time and distance all we have to do is find the average speed.

Average Speed = distance ÷ time

So 150 ÷ 15 = 10 km/h

3 0

3 years ago

If you count by 5's, you have to count times.