First, you should substitute a, b, and c with -3, 9, and 4, so you get 4(-3(2)+9+4)
Next, following PEMDAS, you solve everything in the (,), leaving you with 4(7).
Lastly, your answer is 28.
Answer:
Discontinuity at (−4, −3), zero at (−1, 0)
Step-by-step explanation:
The expression simplifies to ...
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This is undefined at x=-4, hence there is a discontinuity there, and is zero for x=-1.
There is a discontinuity at x=-4, and a zero at (-1, 0).
This ones a bit of a trick question, since whether the integers are even or odd doesn't really matter. What does matter, is that consecutive odd integers are 2 numbers apart (as are consecutive even integers).
So again, if the first of the odd integers is the variable n
the consecutive odd integers after it can be written as:
n+2 , n+4, etc...
So the sum of four consecutive odd integers can be written as:
sum = n + (n+2) + (n+4) + (n+6)
Simplify:
sum = 4n + 12
And finally rearrange to solve for n:
= n
This can also be written as:
- 3 = n
Whichever way you prefer.
II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
The 2nd one, with the pink is correct it is reflecting across the x axis