Answer:
a) The margin of error for a 90% confidence interval when n = 14 is 18.93.
b) The margin of error for a 90% confidence interval when n=28 is 12.88.
c) The margin of error for a 90% confidence interval when n = 45 is 10.02.
Step-by-step explanation:
The t-distribution is used to solve this question:
a) n = 14
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 14 - 1 = 13
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.7709
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The margin of error for a 90% confidence interval when n = 14 is 18.93.
b) n = 28
27 df, T = 1.7033

The margin of error for a 90% confidence interval when n=28 is 12.88.
c) The margin of error for a 90% confidence interval when n = 45 is
44 df, T = 1.6802

The margin of error for a 90% confidence interval when n = 45 is 10.02.
<span>the sequence is geometric, with the common ratio being 1/6 (48 * 1/6 = 8
The formula for a geometric sequence is cr^n where "c" is a constan</span>t <span> and "r" is the common ratio
=48(1/6)^n.
A geometric series converges only if the absolute value of the common ratio is < It diverges if the ratio is >or equal to 1.
the ratio is 1/6, so the sequence converges.
Now in this case, the limit seems to approach 0,
values can only keep getting smaller.
If the limit approaches 0, then the series will converge to a definite sum
S = c / (1 - are)
S = 48 / (1 - 1/6)
S = 57.6
series converges, has a limit of 0,
sum of 57.6.
hope this helps</span>
1. One quater and one nicle 2. Three Dimes 3. 6 nickels 4. One dime and four nickles 5. two nickles and two dimes i think
5/16
this is the fraction
You choose
Answer : 4123
Explanation: