All categories

3 years ago

Find missing measure

Mathematics

1 answer:

Genrish500 [490]3 years ago

8 0

Answer:

Step-by-step explanation:

∠Q = 180-∠T = 89°

∠S = 360-∠T-∠Q-∠R = 360-91-89-27 = 153°

You might be interested in

I need help like RIGHT NOW!!!!!

Temka [501]

Part A: Barry has his own job. Barry saves his earned money and doesn't spend it. He cuts down on buying things he doesn't need. After a while, Barry will have enough money saved to go on vacation with his family.

Part B: Barry has a job, but he buys all kinds of thing with his money. He saves no money and wastes it on things he doesn't need. he gives his money aws=ay to his friends. Barry will not have money for a family vacation.

8 0

3 years ago

Read 2 more answers

4. A light bulb was being tested so it was left on

PolarNik [594]

Answer:

696 hours

Step-by-step explanation:

8 0

3 years ago

The height of a parallelogram is 4.5 CM the base is twice the height what is the area

stepan [7]

Answer:

121.5

Step-by-step explanation:

Area is bases times height. The height is 4.5. And the bases is double the height. So 4.5 times 2 is 27. so we back to area wich is now 4.5 times 27 which is 121.5

<h2>A = b times h </h2><h2 /><h2>h times 2 = b </h2><h2 />

3 0

3 years ago

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

<u>Perimeter of Triangle ABC</u>

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago

Help!!!I gotta turn this in by Friday

Shkiper50 [21]

Answer:

I would help you but there are No questions?

Step-by-step explanation:

5 0

3 years ago

Find missing measure​

Find missing measure