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3 years ago

Summary of water filtration

Biology

1 answer:

andrew11 [14]3 years ago

7 0

Explanation:

Water filtration is the process of removing or reducing the concentration of particulate matter, including suspended particles, parasites, bacteria, algae, viruses, and fungi, as well as other undesirable chemical and biological contaminants from contaminated water to produce safe and clean water for a specific purpose ...

Water filtration can provide better tasting and better smelling drinking water by removing chlorine, chemicals, pesticides, heavy metals and bacterial contaminants. ... Drinking clean, filtered water protects the body from disease and leads to overall greater health and energy.

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Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based

zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

$p^{2} = f(TLTL)$

$2pq = f(TSTL)$

$q^{2} = f(TSTS)$

So, if the population is in balance:

$P = p^{2}$

$H = 2pq$

$Q = q^{2}$

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

$f(TLTL) = P = p^{2} = 0,4^{2} = 0,16$

$f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48$

$f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36$

I hope you have a SUPER day!

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