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SOVA2 [1]
3 years ago
11

Planets X and Y orbit each other in space. Which changes would have the greatest effect on increasing the gravitational attracti

on between the two planets?
Group of answer choices

Halving the mass of planet X and doubling the distance between the planets

Halving the mass of planet X and halving the distance between the planets

Doubling the mass of planet X and halving the distance between the planets

Doubling the mass of planet X and doubling the distance between the planets
Chemistry
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

halving, the mass of planet X and halving the distance between the planets

You might be interested in
Locations Cost of land Cost of equipment Cost of mining and reclamation Time taken to mine the area 1 $100,000 $10,000 $5,000 pe
mario62 [17]

Answer:

Location 2 will cost the least to the company to mine.

Explanation:

a) Data and Calculations:

Locations  Cost of land     Cost of       Cost of mining      Time taken to

                                        equipment   and reclamation    mine the area

1                 $100,000      $10,000         $5,000 per day        30 days

2                 $35,000       $6,000          $4,500 per day        45 days

3                 $30,000       $7,500          $3,500 per day       120 days

4                 $40,500       $8,000          $7,000 per day        65 days

Locations  Cost of land     Cost of       Cost of mining                      Total

                                        equipment   and reclamation                    Costs

1                 $100,000      $10,000         $150,000 ($5,000 * 30)  $260,000

2                 $35,000       $6,000         $202,500 ($4,500 * 45)   $243,500

3                 $30,000       $7,500         $420,000 ($3,500 * 120)  $457,500

4                 $40,500       $8,000         $445,000 ($7,000 * 65)   $503,500

7 0
3 years ago
(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g
Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

5 0
3 years ago
PLEASE HELP!!
Elis [28]
The answer should be 502

3 0
4 years ago
Given that the free energy of the twist-boat conformer of cyclohexane is 5.3 kcal/mol greater than that of the chair conformer,
marishachu [46]

Answer:

0.013%

Yes, it does. The answer agrees with the statement.

Explanation:

Both conformers are in equilibrium, and it can be represented by the equilibrium equation K:

K = [twist-boat]/[chair]

The free energy between them can be calculated by:

ΔG° = -RTlnK

Where R is the gas constant (8.314 J/mol.K), and T is the temperature (25°C + 273 = 298 K).

ΔG° = 5.3 kcal/mol * 4.182 kJ/kcal = 22.165 kJ/mol = 22165 J/mol

22165 = -8.314*298*lnK

-2477.572lnK = 22165

lnK = -8.946

K = e^{-8.946}

K = 1.30x10⁻⁴

[twist-boat]/[chair] = 1.30x10⁻⁴

[twist-boat] = 1.30x10⁻⁴[chair]

The percentage of the twist-boat conformer is:

[twist-boat]/([twist-boat] + [chair]) * 100%

1.30x10⁻⁴[chair]/(1.30x10⁻⁴[chair] + [chair]) *100%

0.013%

The statement about the conformers is that the chair conformer is more stable, and because of that is more present. So, the answer agrees with it.

3 0
3 years ago
The silver nitrate in 20.00 mL of a certain solution was allowed to react with sodium chloride according to the following equati
valentinak56 [21]

Answer:

The answer to your question is: 0.1 M

Explanation:

data

Volume of AgNO3 = 20.00 ml

                   1000 ml --------------  1 l

                       20 ml --------------- x              

          x = 20x 1 /1000 = 0.02

AgCl = 0.2867 g

MW of AgCl = 35.45 + 107.9 = 143.35 g

                       143.35 g -------------- 1 mol

                       0.2867 g -------------  x

  x = 0.2867 x 1 / 143.35 = 0.002 moles of AgCl

   From the balance reaction we see that the proportion of AgNO3 to AgCl is 1:1, then

           1 mol of AgNO3 -------------------- 1 mol of AgCL

                 x                   ---------------------  0.002 moles of AgCl

 x = 0.002 moles of AgNO3

   This moles of AgNO3 are in 20 ml or 0.02 liters

So, Molarity = # moles/liter

      Molarity = 0.002 moles/ 0.02 = 0.1 M

4 0
3 years ago
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