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BartSMP [9]
3 years ago
10

How will increasing the pressure on the system affect this equilibrium reaction?

Chemistry
1 answer:
eduard3 years ago
3 0
No effect because pressure only affects equilibrium in gas state reactions
Hehjsjshhshshshsh
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How long will it take a plane to go 800 miles if it’s traveling at an average speed of 650 miles per hour?
Naya [18.7K]

If there is NO wind resistance, just plain math, this is the answer.

To get the answer you would divide 800 by 650.

800/650 = 1.230769231 (exactly)

That would translate to exactly <span>1 hour 13 minutes and 50 seconds </span>

5 0
3 years ago
Read 2 more answers
What is the density of a book with a mass of 60g and a volume of 20 cm3?
Vaselesa [24]

Answer:

2.5 g/cm3 .

Explanation:

Density is mass in grams over volume in cubic centimeters. So it is 25 g 10 cm 3 =2.5 g/cm 3 The unit is grams per cubic centimeter. NB - density can also be kilograms over cubic meters Hope this helps!

6 0
3 years ago
To measure the volume of the blood system of an animal, the following experiment was done. A 1.0-mL sample of an aqueous solutio
Artyom0805 [142]

Answer:199mL

Explanation:

Let V ml be the volume of blood in animal.

When 1.0 ml sample is added, total volume becomes V+1.0ml. Its activity is 1000 dpm.

After equilibrium, 2.0 ml of the sample had activity of 10 dpm.

Hence, after equilibrium, the activity of V+1.0 ml of blood sample will be 10/2 (V+1.0ml)=1000dpm

Hence, V=199ml.

4 0
3 years ago
The atmosphere is about 21% oxygen. At a pressure of 749 torr, what is the partial pressure of O2?
Kitty [74]

Answer:

157.29 Torr

Explanation:

This question may be solved by the mole fraction.

Mole fraction → Moles of gas / Total moles = Partial pressure of gas / Total pressure

If the atmosphere is about 21% you assume that the mole fraction is 0.21 so:

0.21 = Partial pressure of gas / Total pressure

0.21 = Partial pressure of gas / 749 Torr

Partial pressure of the gas = 749 Torr . 0.21 →  157.29 Torr

3 0
3 years ago
What is the Ksp expression for the dissociation of calcium oxalate?Immersive Reader
skelet666 [1.2K]

Answer:

Ksp = [Ca⁺²] × [C₂O₄⁻²]

Explanation:

Step 1: Write the balanced reaction for the dissociation of calcium oxalate

CaC₂O₄(s) ⇄ Ca⁺²(aq) + C₂O₄⁻²(aq)

Step 2: Write the expression for the solubility product constant (Ksp) of calcium oxalate

The solubility product constant is the equilibrium constant for the dissociation reaction, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids nor pure liquids because their activities are 1.

Ksp = [Ca⁺²] × [C₂O₄⁻²]

3 0
3 years ago
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