Answer:
Heat energy or kinetic energy
Explanation:
Because heat energy is obtained by heating the water. Then water molecules gain kinetic energy causing them to vibrate frequently, leaving their positions and eventually spread out to become a gas.
Answer: the answer is B
Explanation: i go to connexus i had this question
Data:
![T \ = \ 297.15K\\E_{A} \ = \ 48400 \frac{J}{mol}\\R \ = \ 8.314 \frac{J}{mol \ K}\\k_{0} = 0.0140s^{-1}](https://tex.z-dn.net/?f=T%20%5C%20%3D%20%5C%20297.15K%5C%5CE_%7BA%7D%20%5C%20%3D%20%5C%2048400%20%5Cfrac%7BJ%7D%7Bmol%7D%5C%5CR%20%5C%20%3D%20%5C%208.314%20%5Cfrac%7BJ%7D%7Bmol%20%5C%20K%7D%5C%5Ck_%7B0%7D%20%3D%200.0140s%5E%7B-1%7D)
Explanation:
The rate constant as a function of the temperature can be expressed using the Arrhenius equation, as follows,
![k(T) \ = \ A e^{ \frac{-E_{A}}{RT}}](https://tex.z-dn.net/?f=k%28T%29%20%5C%20%3D%20%5C%20A%20e%5E%7B%20%5Cfrac%7B-E_%7BA%7D%7D%7BRT%7D%7D)
Then, find a value for the constant A, according to the data given in the exercise,
![A \ = \frac{ k_{0} }{ e^{ \frac{-E_{A}}{RT}}}](https://tex.z-dn.net/?f=A%20%5C%20%3D%20%5Cfrac%7B%20k_%7B0%7D%20%7D%7B%20e%5E%7B%20%5Cfrac%7B-E_%7BA%7D%7D%7BRT%7D%7D%7D)
![A \ = 4512841.2s^{-1}](https://tex.z-dn.net/?f=A%20%5C%20%3D%204512841.2s%5E%7B-1%7D)
As the rate constant has units
then, the reaction corresponds to one of first order. Then, the reaction corresponds to:
![r \ = \ k(T) \ [A]](https://tex.z-dn.net/?f=r%20%5C%20%3D%20%5C%20k%28T%29%20%5C%20%5BA%5D)
Which tell the amount of mass (mol) is produced by second per unity of volume.
Answer:
If the reaction goes twice fast, the reaction rate corresponds to,
![r \ = \ 2 \ r_{0}](https://tex.z-dn.net/?f=r%20%5C%20%3D%20%5C%202%20%5C%20r_%7B0%7D)
The expression above can be reduced to:
![k(T) \ = \ 2 \ k_{0}](https://tex.z-dn.net/?f=k%28T%29%20%5C%20%3D%20%5C%202%20%5C%20k_%7B0%7D)
Replacing k(T) in order to obtain the temperature T,
![4512841.2 \ e^{\frac{-E_{A}}{RT}}} \ = \ 2k_{0}\\e^{\frac{-E_{A}}{RT}}} \ = \frac{2k_{0}}{4512841.2}\\\frac{-E_{A}}{RT}} \ = \ ln( \frac{2k_{0}}{4512841.2} )\\\frac{-E_{A}}{R \ ln(\frac{2k_{0}}{4512841.2} ) }} \ = \ T](https://tex.z-dn.net/?f=4512841.2%20%5C%20e%5E%7B%5Cfrac%7B-E_%7BA%7D%7D%7BRT%7D%7D%7D%20%5C%20%3D%20%5C%202k_%7B0%7D%5C%5Ce%5E%7B%5Cfrac%7B-E_%7BA%7D%7D%7BRT%7D%7D%7D%20%5C%20%3D%20%5Cfrac%7B2k_%7B0%7D%7D%7B4512841.2%7D%5C%5C%5Cfrac%7B-E_%7BA%7D%7D%7BRT%7D%7D%20%5C%20%3D%20%5C%20ln%28%20%5Cfrac%7B2k_%7B0%7D%7D%7B4512841.2%7D%20%29%5C%5C%5Cfrac%7B-E_%7BA%7D%7D%7BR%20%5C%20ln%28%5Cfrac%7B2k_%7B0%7D%7D%7B4512841.2%7D%20%29%20%7D%7D%20%5C%20%3D%20%5C%20T)
Replacing all values,
![T \ = \ 308K](https://tex.z-dn.net/?f=T%20%5C%20%3D%20%5C%20308K)