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emmainna [20.7K]
4 years ago
11

What mineral is the hardest known substance in nature?

Chemistry
2 answers:
Darya [45]4 years ago
6 0

Answer:

The hardest known substance in nature is diamond.

Explanation:

It is rated a 10 on the Moh's hardness scale and it can only be cut by another diamond!

shusha [124]4 years ago
3 0
The mineral that is the hardest known substance in nature is a diamond. 
Hope this helps. 



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I'll give 50 pts and brainliest
e-lub [12.9K]

Answer:

Response is below

Explanation:

The different types of mining are underground, surface, placer, and in-situ. Underground mining uses various materials to excavate resources from beneath the surface of the Earth. Surface mining is a category of mining that in which soil and rock overlying the mineral deposit are removed. Placer mining is the mining of stream bed deposits for minerals. In-situ mining is a mining process used to recover minerals such as copper and uranium through boreholes drilled into a deposit.

3 0
3 years ago
alculate the energy for vacancy formation in silver, given that the equilibrium number of vacancies at 800°C (1073 K) is 3.6 × 1
bearhunter [10]

The answer & explanation for this question is given in the attachment below.

4 0
3 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
How much heat (kj) is required to convert 3.12 moles of liquid benzene at 75.1°c to gaseous benzene at 115.1°c?
Tems11 [23]
The total energy includes sensible heat to raise the temperature from 75.1°C to the boiling point. It also includes the latent heat to convert the liquid to gas. Then, it also includes sensible heat from he boiling point to 115.1°C. The equation is:

Energy = nCp,liquid(T,bp - T₁) + nΔH + nCp,gas(T₂ - T,bp)
where
n is the number of moles
T,bp is the boiling point of benzene at 80.1°C
Cp,liquid = 134.8 J/mol·°C
Cp,gas = 82.44 J/mol·°C
ΔH = 87.1 J/mol

Energy = (3.12 moles)(134.8 J/mol·°C)(80.1°C - 75.1°C) + (3.12 moles)(87.1 J/mol) + (3.12 moles)(82.44 J/mol·°C)(115.1°C - 80.1°C)
Energy = 11,377.08 J
3 0
3 years ago
A rigid tank is divided into two equal volumes. One side contains 2 kmol of nitrogen N2 at 500 kPa while the other side contains
k0ka [10]

Answer:

The partial pressure of the CO_2 in the final mixture is 200 kPa.

Explanation:

Pressure of nitrogen gas when the two tanks are disconnected = 500 kPa

Pressure of the carbon-dioxide gas when the two tanks are disconnected = 200 kPa

Moles of nitrogen gas =n_1= 2 kmol

Moles of carbon dioxide gas =n_2=8 kmol

After connecting both the tanks:

The total pressure of the both gasses in the tank = p = 250 kPa

According to Dalton' law of partial pressure:

Total pressure is equal to sum of partial pressures of all the gases

Partial pressure of nitrogen =p_{N_2}^o

Partial pressure of carbon dioxide=p_{CO_2}^o

p_{N_2}^o=p\times \frac{n_1}{n_1+n_2}

p_{N_2}^o=250 kPa\times \frac{0.2}{0.2+0.8}=50 kPa

p_{CO_2}^o=p\times \frac{n_2}{n_1+n_2}

p_{CO_2}^o=250 kPa\times \frac{0.8}{0.2+0.8}=200 kPa

The partial pressure of the CO_2 in the final mixture is 200 kPa.

7 0
3 years ago
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