Noble gases react very unwillingly, because the outermost shell of electrons orbiting the nucleus is full, giving these gases no incentive to swap electrons with other elements. As a result, there are very few compounds made with noble gases. Like its noble gas comrades, neon is odorless and colorless.
Lower energy and more disorder
Answer:
Option A
Explanation:
Temperature of a body is due to the heat gained or loss. During a phase change, the atoms or molecules of a substance are undergoing change is temperature due to which no temperature change is observed during phase change. The heat in the transition phase is used to break bonds and the change in temperature is felt when kinetic energy change is complete. During transition, the average kinetic energy of the molecules remains unchanged and hence during a phase change a temperature do not changes until unless the phase change is completed.
Hence, option A is correct
Molarity is the ratio of the moles of a solute to the total liters of a solution. The solution includes both the solute and the solvent. Molality, on the other hand, is the ratio of the moles of a solute to the kilograms of a solvent.
Explanation:
It is given that,
Initial orbit of electrons, 
Final orbit of electrons, 
We need to find energy, wavelength and frequency of the wave.
When atom make transition from one orbit to another, the energy of wave is given by :

Putting all the values we get :

We know that : 
So,

Energy of wave in terms of frequency is given by :


Also, 
is wavelength
So,

Hence, this is the required solution.