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vaieri [72.5K]
3 years ago
7

The crust and solid upper mantle make up Earth's a)continents b)lithosphere c)ocean basins

Chemistry
2 answers:
padilas [110]3 years ago
8 0

Answer:

B

Explanation:

Is correct because i have taken the test and aced it

Margarita [4]3 years ago
3 0

Answer:

B) lithosphere

Explanation:

The crust and solid upper mantle make up Earth's lithosphere.

Hope this helps

-Amelia

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Fumaric acid is an organic compound composed of 41.39% , 3.47% , and the rest oxygen. If 0.288 mol of fumaric acid has a mass of
Gnesinka [82]

Answer:

Molecular formula: C₄H₄O₄

Empirical formula: CHO

Explanation:

Centesimal composition of fumaric acid:

41.39% C

3.47% H

(100% - 41.39% - 3.47%) = 55.14% O

In 100 g of fumaric, we got:

41.39 g of C

3.47 g of H

55.14 g of O

If we take account that we have x mol of fumaric in x mass of the same compound (g/mol), we can determine molar mass.

33.4 g / 0.288 mol → 116 g/mol

Now, we can prepare this rules of three:

In 100 g of fumaric we have 41.39 g of C, 3.47 g of H, 55.14 g of O

Then 116 g of fumaric will have:

(116 . 41.39) / 100 = 48 g C

(116 . 3.47) / 100 = 4 g H

(116. 55.14) / 100 = 64 g O

If we convert the mass to moles, we reach the molecular formula:

48 g . 1mol /12 g = 4 moles C

4 g . 1mol /1g = 4 moles H

64 . 1mol/16 g = 4 moles O

Molecular formula: C₄H₄O₄

Empirical formula: CHO

5 0
4 years ago
Read 2 more answers
How is a new moon the same as or different from a total lunar eclipse
yarga [219]

Explanation:

Both new moon and lunar eclipse occur when the moon is in the same plane the sun and the earth. However, both are different because of the relative position of the moon in its orbit – relative to earth. In a new moon, the moon is in between the earth and the sun, while in a lunar eclipse, the earth us in between the moon and the sun.

Learn More:

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3 years ago
What mass of oxygen forms from 71.89 g CO2? Use the periodic table to find molar masses.
Paraphin [41]
Atomic mass C = 12.0107
Atomic mass O= 15.9994
Calculate the molecular mass of the CO2
12.0107 + (2 x 15.9994) = 44.0095

Multiply the mass of CO2 by the conversion factor that relate the O mass to the molecular mass of CO2 to find the mass of O in the 71.89g of CO2

71.89 g CO2 x (2 x 15.9994) / 44.0095 =

52.2703900748702

52.27 g O

8 0
4 years ago
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3 years ago
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What pattern do you observe in the coefficients of the hydrocarbon (CxHy) and water (H2O)? How do you explain this pattern?
balu736 [363]

The coefficients of the hydrocarbon and water is 61 and it is explained below.

Explanation:

We have to  balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2.  Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.

The unbalanced chemical equation is

C₈H₁₈ + O₂ → CO₂ + H₂O

To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by  8  to get  8  atoms of carbon on the products side.

C₈H₁₈ + O₂ → 8 CO₂ + H₂O

Now, we have 18  on the reactant side and  2  on the products side, so multiply the water molecule by  9  to get

C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O

8 * 2 atoms O + 9 *1 atoms O = 25 atoms O

By adding fractional coefficient to O₂ we get

C₈H₁₈ + \frac{25}{2}O₂ → 8 CO₂ + 9 H₂O

Multiply all the coefficients by 2 we get,

2C₈H₁₈ + (\frac{25}{2} * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O

The balance equation is

2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

Add the coefficients to get their sum

= 2 +25 + 16 +18 = 61

Thus, The coefficients of the hydrocarbon and water is 61

6 0
3 years ago
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