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Lapatulllka [165]
3 years ago
13

Which statement about the elements in the periodic table is true

Chemistry
2 answers:
miss Akunina [59]3 years ago
8 0

Answer:

The reactivity of alkali metals increases as atomic mass increases.

Explanation:

There are six elements in the periodic table that can be classified as alkali metals. These elements are extremely reactive and it is correct to say that the reactivity of alkali metals increases as the atomic mass increases.

These metals can be found in the IA family of the periodic table and contain the names: Lithium, Sodium, Potassium, Rubidium, Cesium, Francium.

egoroff_w [7]3 years ago
6 0

A. The number of valence electrons increases as atomic mass increases. == Generally true for the representative elements since atomic mass generally increases with increasing Z.  

B. The reactivity of alkali metals increases as atomic mass increases. == True. Atomic mass increases down the column and so does reactivity  

C. The reactivity of the halogens increases as atomic mass increases. == False. Reactivity decreases down the column.  

D. The number of valence electrons decreases across a period. == False. In general, the number of valence electrons increases across a period, particularly for the representative elements.

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At a certain temperature this reaction follows second-order kinetics with a rate constant of Suppose a vessel contains at a conc
Norma-Jean [14]

The question is incomplete, here is the complete question:

At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1 M⁻¹s⁻¹

2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)

Suppose a vessel contains SO₃ at a concentration of 1.44 M. Calculate the concentration of SO₃ in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.

<u>Answer:</u> The concentration of SO_3 in the vessel after 0.240 seconds is 0.24 M

<u>Explanation:</u>

For the given chemical equation:

2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 14.1M^{-1}s^{-1}

t = time taken= 0.240 second

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 1.44 M

Putting values in above equation, we get:

14.1=\frac{1}{0.240}\left (\frac{1}{[A]}-\frac{1}{1.44}\right)

[A]=0.245M

Hence, the concentration of SO_3 in the vessel after 0.240 seconds is 0.24 M

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Explanation:

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