Explanation:
This indicates that there are more hydroxide ions in solution than there were in the original water. This is because some magnesium hydroxide has dissolved. Calcium hydroxide solution is referred to as "lime water". A liter of pure water will dissolve about 1 gram of calcium hydroxide at room temperature.
Answer: Tin has 48 electrons, 69 neutrons, and 50 protons.
Explanation:
Answer:
a) IUPAC Names:
1) (<em>trans</em>)-but-2-ene
2) (<em>cis</em>)-but-2-ene
3) but-1-ene
b) Balance Equation:
C₄H₁₀O + H₃PO₄ → C₄H₈ + H₂O + H₃PO₄
As H₃PO₄ is catalyst and remains unchanged so we can also write as,
C₄H₁₀O → C₄H₈ + H₂O
c) Rule:
When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.
d) C is not Geometrical Isomer:
For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.
Answer:
The pH of the buffer is 7.0 and this pH is not useful to pH 7.0
Explanation:
The pH of a buffer is obtained by using H-H equation:
pH = pKa + log [A⁻] / [HA]
<em>Where pH is the pH of the buffer</em>
<em>The pKa of acetic acid is 4.74.</em>
<em>[A⁻] could be taken as moles of sodium acetate (14.59g * (1mol / 82g) = 0.1779 moles</em>
<em>[HA] are the moles of acetic acid (0.060g * (1mol / 60g) = 0.001moles</em>
<em />
Replacing:
pH = 4.74 + log [0.1779mol] / [0.001mol]
<em>pH = 6.99 ≈ 7.0</em>
<em />
The pH of the buffer is 7.0
But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,
this pH is not useful to pH 7.0
<em />
Answer:
D) C5H12
Explanation:
The rate of evaporation of a solution depends on the nature of intermolecular forces in the solution. The stronger the magnitude of intermolecular forces present the lower the rate of evaporation.
If we consider the compounds; C7H15OH, C7H15NH2 and C6H13COOH, the presence of polar groups implies that dipole-dipole interactions are present in the molecule leading to stronger intermolecular interaction and a slower rate of evaporation.
On the other hand; C7H16 and C5H12 are alkanes. The intermolecular forces that exists between their molecules is the weak dispersion forces. However, the magnitude of dispersion forces increases as the molecular mass of the compound increases.
Hence, C5H12 has the fastest rate of evaporation since it has the lowest molecular mass.
