Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
Phosphorus, copper, carbon monoxide, hydro cyanic acid, nitrates, potassium chlorate, and aniline are some of the examples of poison that can be identified by a color test according to forensic pathology.
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Answer:
Option D. Saturated alkane
Explanation:
To know which option is correct, it is important that we know what saturated and unsaturated compounds are in this context.
Saturated hydrocarbons are compounds which has only carbon to carbon single bonds (C–C) in its chain. A very good example of such compound is the Alkanes.
Unsaturated hydrocarbons are compounds which has either a carbon to carbon double bond (C=C) or a carbon to carbon triple bond (C≡C) in its chain. Examples of such compounds include alkenes and alkynes.
Now, let us answer the question given above bearing the meaning of saturated and unsaturated compounds in mind.
The compound given above contains only carbon to carbon (C–C) single bond.
Therefore, the compound is a saturated alkane.
