Answer:
(a) Speed = 6.875 m/s
(b) Kinetic Energy = 1.70 kJ
(c) Average power = 1.06 kW
Step-by-step explanation:
Given:
d = 5.5 m
t = 1.6 s
W = 706 N
Part (a)
Using the equation of motion with the assumption of zero initial speed:
The speed of the sprinter then become:
Part (b)
Convert the weight of the sprinter to mass:
KE (Kinetic Energy) can then be calculated as:
Part (c)
The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as
**y=x+2
when x=0,y=2; A(0,2)
when x=1,y=3; B(1,3)
**y=-x+8
when x=0,y=8; C(0,8)
when x=5,y=-3; D(5,-3)
The solution from the graph is S(2,4).
Answer:
The answer is %14.
Step-by-step explanation:
Lets consider that there are 100 people attending to the gym class.
Then we know that 45 person is going to Zumba training.
%5 of people attends all the classes in the gym. Means 5 person attends all the classes. Lets subtract them from 45 person. 45-5=40. We have 40 person left.
%15 of people attends Zumba and yoga, %21 of people attends Zumba and weight lifting. First we need to substract first %5 which attends all classes in the gym from both clusters.
21-5=16 and 15-5-10
We have 10+16=26 person which attends Zumba and one more class. Lets subtract those from Zumba cluster 40-26=14. 14 person is only attending to Zumba classes
Answer:
<h2>
65%</h2>
Step-by-step explanation:
<h3>
Given: Full capacity= 200000 litres
</h3><h3>
</h3><h3>
Amount of fuel used during flight= 130000 litres
</h3><h3>
</h3><h3>
Now, finding percentage of fuel used on the flight.
</h3><h3>
</h3><h3>
∴ Percentage of fuel used= </h3><h3>
</h3><h3>
Solving it, we will get </h3><h3>
</h3><h3>
∴ 65% of fuel capacity been used in this flight.</h3>
