Okay so to figure out this problem you need to say 5/1 times 3/4 which equals 15/4 We know that we cant have an improper fraction so we divide this and it equals 3
It would be C since it’s in between both inequalities and in the shaded region.
Simplify. Combine like terms
12x - 9x = 3x
7 - 15 = -8
3x - 8 is your answer
hope this helps
<h3>
Answer: Choice D</h3>

Domain = [-3, infinity)
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Work Shown:

In step 2, we replaced every x with g(x)
In step 3, we plugged in g(x) = sqrt(x+3)
The domain of g(x) is [-3, infinity), so this is the domain of
as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.
This is how you do it hope this helps.