Answer:
A. ΔS°rxn decreases
B. ΔS°rxn decreases
C. ΔS°rxn has little or no change
D. ΔS°rxn increases
Explanation:
The change in entropy (ΔS°rxn) is related to the change in the number of moles of gases (Δn(gas) = n(gas products) - n(gas reactants)). If the number of moles of gases increases, there are more possible microstates and entropy increases. The opposite happens when there are less gaseous moles. And little or no change in entropy is expected when the number of moles of reactants and products is the same.
<em>A. K(s) + O₂(g) ⟶ KO₂(s)</em>
Δn(gas) = 0 - 1 = -1
ΔS°rxn decreases
<em>B. CO(g)+ 3 H₂(g) ⟶ CH₄(g) + H₂O(g)</em>
Δn(gas) = 2 - 4 = -2
ΔS°rxn decreases
<em>C. CH₄(g) + 2 O₂(g) ⟶ CO₂(g)+ 2 H₂O(g)</em>
Δn(gas) = 3 - 3 = 0
ΔS°rxn has little or no change
D. N₂O₄(g) ⟶ 2 NO(g) + O₂(g)
Δn(gas) = 3 - 1 = 2
ΔS°rxn increases
Answer:
An input of heat energy Yr don't you know stupied
Answer:
B. Watermelon
Explanation:
Watermelon is the only option with a definite shape that wouldn't change if you put it in a bowl
