Question

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 14.4 g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced.
Round your answer to 3 significant digit

Answer 1

Answer:

$\boxed{\text{0.0901 mol}}$

Explanation:

$\text{Moles} = \text{14.4 g } \times \dfrac{\text{1 mol}}{\text{159.81 g}} = \text{0.0901 mol}\\\\\text{ The sample contains \boxed{\textbf{0.0901 mol}} of bromine}$