Answer:
Explanation:
Given that,
Number of turns of coil
N = 50 turns
Initial area of plane
A1 = 0.18 m²
The coil it stretch to a no area in time t = 0.1s
No area implies that the final area is 0, A2 = 0 m²
Constant magnetic field strength
B = 1.51 T
EMF?
EMF is given as
Using far away Lenz law
ε = —N• dΦ/dt
Where Φ = BA
Then,
ε = —N• d(BA)/dt
Since B is constant,
ε = —N•B dA/dt
ε = —N•B (∆A/∆t)
ε = —N•B(A2—A1)/(t2-t1)
ε = —50 × 1.51 (0—0.18)/(0.1—0)
ε =—75.5 × —0.18 / 0.1
ε = 135.9 V
The induced EMF is 135.9V
Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.
Since the area lines in the plane, then the induced emf will be out of the page
Answer:
F = 0
Explanation:
The net force acting on an object is given by the product of mass and acceleration. We know that acceleration is equal to the rate of change of velocity.
Net force,
F = ma
The skier is traveling at a constant velocity, it means there is no change in velocity i.e. acceleration is equal to 0. Hence, the force on her is 0.
<span>It takes only one atom to make hydrogen; however, hydrogen is commonly found as H2, meaning two atoms make up hydrogen. Because of this, hydrogen is known as a diatomic element
The answer is prob A.1 but you didnt' give me a formula.</span>
Answer:
Net force equals 0
Explanation:
Newton's first law states that an object at rest tends to remain at rest, and an object in motion tends to remain in motion with a constant velocity (constant speed and direction of motion), unless it is acted on by a nonzero net force. Note that the net force is the sum of all the forces acting on an object.
On the dog's return trip (between <em>t</em> = 10 and <em>t</em> = 12.5 seconds), the slope of the position function is steeper than during the first 5 seconds, which means the dog ran home faster. The only option that captures this is D.
You can check to make sure that the dog indeed runs twice as fast on the return trip. The slope of the position function during the first 5 seconds is
(change in position) / (change in time) = (5 - 0) / (5 - 0) = 5/5 = 1
while during the return trip, it is
(0 - 5) / (12.5 - 10) = -5/2.5 = -2
Ignoring the sign (which only indicates the direction in which the dog was running), we see that the dog's speed on the return trip was indeed twice as high as during the first 5 s.
