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Sonja [21]
3 years ago
11

Find the area of the kite

Mathematics
2 answers:
Ket [755]3 years ago
4 0
72 cm2

12x11/2=66

12x1/2=6

66+6=72
Ede4ka [16]3 years ago
3 0

Answer:

396

Step-by-step explanation:

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A rectangular prism is 3 inches long, 4 inches wide and 8 inches tall. What is the length of its
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The longest diagonal is about 8.9 inches. The longest length is going to be between the two longest lengths, the width and the height. The Pythagorean theorem is a^2 + b^2 = c^2. Plug the width and height into a and b of the Pythagorean equation. (4)^2 + (8)^2 = c^2. Now simplify the equation. 16 + 64 = c^2. 80 = c^2. Now find the square root of each side. (sqrt)80 = (sqrt)c^2. If you simplify this, you will find that c is equal to about 8.9 inches.
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3 years ago
A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500
Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking,\frac{d(w)}{dt} = 3 ft/sec

Rate at which the man is walking,\frac{d(m)}{dt} = 2 ft/sec

Collective rate of both, \frac{d(m+w)}{dt} = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min  = 20 min

Now,

Distance traveled by man and woman are m and w ft respectively.

⇒ m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft

⇒ w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\  ft

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate \frac{dh}{dt} .

Lets calculate h.

Applying Pythagoras formula.

⇒ h^2=(m+w)^2+500^2  

⇒ h=\sqrt{(2400+2700)^2+500^2} = 5124.45

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ h^2=(m+w)^2+500^2

⇒ 2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt}  + \frac{d(500)}{dt}

⇒ \frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}                         ...as \frac{d(500)}{dt}= 0

⇒ Plugging the values.

⇒ \frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}                       ...as \frac{d(m+w)}{dt} = 5 ft/sec

⇒ \frac{d(h)}{dt} =4.9761  ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

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3 years ago
What is the yyy-intercept of y=3-4xy=3−4xy, equals, 3, minus, 4, x?
koban [17]
We can rewrite the equation given above as,
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This item asks us to determine the value of the y-intercept. The value is calculated by letting x of the equation be equal to zero. Applying this methodology to the given above,

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3 years ago
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The answer is c alternate exterior angles
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AEFG - ALMN. Find the ratio of AEFG to ALMN.<br><br> A)1:4<br> B)1:2<br> C)2.1<br> D)4:1
vovikov84 [41]

Answer:

C)2 : 1

Step-by-step explanation:

AEFG ≈ ALMN

FG / MN = 4 / 2 = 2/1

So the ratio of AEFG to ALMN = 2 / 1 or 2 : 1

6 0
3 years ago
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