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Igoryamba
3 years ago
9

A truck covers a particular distance in 3 hours with the speed of 60 miles per hour. If the speed is increased by 30 miles per h

our, find the time taken by the truck to cover the same distance.
using y=kx​
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

9514 1404 393

Answer:

  2 hours

Step-by-step explanation:

Time, speed, and distance are related by ...

  d = st

The distance covered is ...

  d = (60 mi/h)(3 h) = 180 mi

Then the time taken at the higher speed is ...

  180 mi = (60 mi/h +30 mi/h)(t)

  t = (180 mi)/(90 mi/h) = 2 h

The time taken at the higher speed is 2 hours.

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Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

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