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2 years ago

A pound of rice crackers cost $2.88. Matthew purchased 1/4 pound of crackers. how much did he pay for the crackers?

Mathematics

2 answers:

sammy [17]2 years ago

7 0

2.88 times 1/4 = $0.72

sergey [27]2 years ago

5 0

The answer would be $0.72. Because 2.88 dived by 4 equals .72. How did I get that answer you ask. Well it states that he buys one fourth of a pound of crackers. 1/4 is a division problem believe it or not. You divide it by four because four is the denominator. It basically is splitting the pound into fourths

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3 years ago

You exercise for one hour each day and you burn 8.5 calories per minute. If you graphed the number of calories you burned as the

mezya [45]

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3 years ago

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Sav [38]

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3 years ago

Brainliest to first correct answer

Artyom0805 [142]

Answer:

Smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

Step-by-step explanation:

We need to find the surface area of all cuboids.

Surface Area of Cuboid A:

Length = 6

Breadth = 25

Height = 4

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2$

So, Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B:

Length = 10

Breadth = 6

Height = 10

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2$

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2$

So, Surface Area of Cuboid C = 740 cm²

So, We get:

Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

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3 years ago

A store is having a sale on almonds and jelly beans. For 3 pounds of almonds and 5 pounds of jelly beans, the total cost is $19

yaroslaw [1]

Answer:

Almond: $7/4 per pound

Jelly Bean: $ 11/4 per pound

Step-by-step explanation:

A: almond

J: jelly bean

3A + 5J = 19 .... multiply 9 each side

27A + 45J = 171 .....(1)

9A + 7J = 35 .....multiply 3 each side

27A + 21J = 105 ....(2)

(1) - (2) 24J = 66

J = 66/24 = 11/4

3A + 5 x 11/4 = 19

3A = 21 / 4

A = 7/4

6 0

2 years ago