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3 years ago

Patrick is driving form Sydney to Canberra. He travels for 288km trip in 4 hours. What's his average speed?

Mathematics

1 answer:

nika2105 [10]3 years ago

3 0

Answer:

v = 72 km/h

Step-by-step explanation:

Given that,

The distance covered by the Patrick, d = 288 km

Time taken, t = 4 hours

We need to find the average speed of Patrick. We know that the average speed of an object is equal to the total distance covered divided by total time taken. Let it is v. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{288\ km}{4\ h}\\\\v=72\ km/h$

So, his average speed is equal to 72 km/h.

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The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

taurus [48]

Answer:

$A\approx 28^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.

$\text{Area}=\frac{1}{2}\text{Base}\times \text{height}$

We know that area of triangle an be found using trigonometry as:

$\text{Area}=\frac{1}{2}\times c\times h$

$\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)$

$3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)$

$3\sqrt{2}=9\cdot \text{sin}(A)$

$9\cdot \text{sin}(A)=3\sqrt{2}$

$\text{sin}(A)=\frac{3\sqrt{2}}{9}$

$\text{sin}(A)=\frac{\sqrt{2}}{3}$

Now, we will use inverse sine to find the value of angle A as:

$A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})$

$A=28.1255057^{\circ}$

$A\approx 28^{\circ}$

Therefore, the measure of angle A is approximately 28 degrees.

3 0

3 years ago

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storchak [24]

Answer:

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Step-by-step explanation:

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3 years ago

1433.4 to the nearest 10

frozen [14]

Answer:

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3 years ago

Simplify 5^3/5^7 leaving your anwser in index form

Wewaii [24]

Steps:

Simplify:

5³/5⁷

= 5³/5⁷

= 5*5*5/ 5*5*5*5*5*5*5

=1/5⁴

=1/625 (Decimal: 0.0016)

Steps by Step:

5³/5⁷

=125/5⁷

=125/78125

=1/625

Answer: =1/625 (Decimal: 0.0016)

Please mark brainliest

<em><u>Hope this helps.</u></em>

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madreJ [45]

Angle B is 45, angle A is 108, angle C is 27

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