$\bf \begin{cases} f(x)=&g(x+1)\\ f(3)=&g(3+1)\\ &g(4)\\[-0.5em] \hrulefill& \hrulefill\\ g(x)=&x^2\\ g(4)=&4^2\\ &16 \end{cases}\qquad \qquad f(3)\implies g(4)\implies 16$

8 0

4 years ago

I NEED HELP FASTT PLEASE

Advocard [28]

It’s the third dot bc X to the tenth power times y divided by three

3 0

3 years ago

Read 2 more answers

How do you estimate fractions who based number fractions, show work plz..

Liono4ka [1.6K]

First if there are 47/80 we have to estimate like 47 is 50 and 82 is 80

7 0

3 years ago

The sum of two numbers is 23. The difference of the numbers is 7.4. What are the two numbers?

Brums [2.3K]

X+y=23
X-y=7.4

X+y=23
y=23-X

X-y=7.4
(23-y)-y=7.4
23-2y=7.4
-2y=-15.6
Y=7.8

X+y=23
X+7.8=23
X=15.2

Therefore the two numbers are 7.8 & 15.2

5 0

2 years ago