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Misha Larkins [42]
3 years ago
8

Factor: 3bc-4ad +6ac-2bd Can you create a rubric for this math question

Mathematics
1 answer:
Trava [24]3 years ago
7 0

Answer:

(3c−2d)(2a+b)

Step-by-step explanation:

3bc−4ad+6ac−2bd

Do the grouping 3bc−4ad+6ac−2bd=(6ac−4ad)+(3bc−2bd), and factor out 2a in the first and b in the second group.

2a(3c−2d)+b(3c−2d)

Factor out common term 3c−2d by using distributive property.

(3c−2d)(2a+b)

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Scarlett is playing a video game she spends 900 minerals to create 18 workers each worker costs the same number of minerals writ
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Answer:

W=50M

Step-by-step explanation:

Since there are 18 workers per 900 minerals, divide out to simplify.

STARTING EQUATION: 900m=18w

SIMPLIFY: divide both sides by 18.

SIMPLIFIED: 50m=1w

There is your answer!

4 0
3 years ago
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Please help due tmr I also have 2 more questions!
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Answer:

17

Step-by-step explanation:

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You make a dessert with lemon gelatin and lime gelatin. What percent of the dessert is lime-flavored? Explain
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Step-by-step explanation:

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2 years ago
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Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
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Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

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3 years ago
-3(X - 8) - (x + 5) - 23
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3

X

−

x

−

4

Step-by-step explanation:

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