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tankabanditka [31]
3 years ago
8

After 15% discount an item cost $22.27 what was the original price?

Mathematics
2 answers:
musickatia [10]3 years ago
6 0
Orig - .15 * orig = 22.27
.85 * orig = 22.27
Original price = 26.20

Sergeeva-Olga [200]3 years ago
6 0

Answer:   $148.47

Step-by-step explanation:

To find the original price of an item cost $22.27 after 15 % discount:

Let x represent the original price

15% of (original price) = $22.27

15% ×  x   = $22.27

\frac{15x}{100}    =  $22.27

We cross multiply

15 x = $22.27  × 100

15 x =  $2227

Divide both-side of the equation by 15

\frac{15x}{15}  =  \frac{2227}{15}

x   =   $148.47

Therefore the original price of the item is $148.47

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(7)*(-8) = -56

(-56) - (-8) = -48

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6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

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