Answer:
Those who were able to keep 12 fishes
Step-by-step explanation:
Given
Total = 20 (each)
Required
Which was able to keep 3/5
First, we need to calculate 3/5 of the total number of fishes
Fish = 3/5 * 20
Fish = (3 * 20)/5
Fish = 60/5
Fish = 12
From the calculation above, only those who keep 12 of the 20 fishes were able to keep 3/5 of their fishes
4 x (3+6) = 12 + 24 ---->Distributive
3 + ( 8 + 2) = 3 + (2 + 8) ---> Commutative
6 x (7 x 3 ) = (6 x 7 ) x 3 --->Associative
