Using the identity:
There are two solutions to this equation:
1)
Since the period of cosine is 2π, so 0 + 2π = 2π will also be a solution to the given equation
2)
Therefore, there are 3 solutions to the given trigonometric equation.
A cube with a volume of 75 cm is dilated bya factor of 5.
1 answer:
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Using the identity:
There are two solutions to this equation:
1)
Since the period of cosine is 2π, so 0 + 2π = 2π will also be a solution to the given equation
2)
Therefore, there are 3 solutions to the given trigonometric equation.
Answer: 11.1 m
Step-by-step explanation:
This can be solved by the Pythagorean theorem where;
c² = a² + b²
c is the hypotenuse which is the distance from the top of the building to the tip of the shadow.
a is the height
c is the length
32² = 30² + b²
b² = 32² - 30²
b² = 1,024 - 900
b² = 124
b = √124
b = 11.1 m
Answer:
3. 150.72 in²
4. 535.2cm²
Step-by-step Explanation:
3. The solid formed by the net given in problem 3 is the net of a cylinder.
The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.
The surface area = Area of the 2 circles + area of the rectangle
Take π as 3.14
radius of circle = ½ of 4 = 2 in
Area of the 2 circles = 2(πr²) = 2*3.14*2²
Area of the 2 circles = 25.12 in²
Area of the rectangle = L*W
width is given as 10 in.
Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in
Area of rectangle = L*W = 12.56*10 = 125.6 in²
Surface area of net = Area of the 2 circles + area of the rectangle
= 25.12 + 125.6 = 150.72 in²
4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)
=
Where,
b = 8 cm
h =