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4 years ago

One major goal of the Progressive movement

Chemistry

1 answer:

muminat4 years ago

3 0

Answer:

The correct answer is option 4-pass laws to help solve economic and social problems

Explanation:

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The progressive movement was from the decade of 1890 until 1920. The objectives were to eliminate the problems of industrialization, corruption, urbanization.

The correct answer is option 4-pass laws to help solve economic and social problems

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Which of the following is an example of a PHYSICAL change?

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Rust on a nail is a chemical change.

Ice melting IS a physical change. Ice is made of water, when you melt ice its still water. Just in a different physical state.

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3 years ago

“Rate” is related to:

alexandr1967 [171]

Answer:

In differential calculus, related rates problems involve finding a rate at which a quantity changes by relating that quantity to other quantities whose rates of change are known. The rate of change is usually with respect to time.

Explanation:

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3 years ago

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How many elements had been discovered by 1860

UkoKoshka [18]

60 elements! I don't exactly know every element known, so if you are asking that, please tell us, but what I do know is that there were 60 elements in the periodic table by 1860.

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3 years ago

Suppose that 98.0g of a non electrolyte is dissolved in 1.00kg of water. The freezing point of this solution is found to be -0.4

Sholpan [36]

Answer:

$\large \boxed{\text{392 u}}$

Explanation:

1. Calculate the molal concentration

The formula for the freezing point depression by a nonelectrolyte is

$\Delta T_{f} = -K_{f}b\\b = -\dfrac{\Delta T_{f}}{ K_{f}} = -\dfrac{-0.465 \, ^{\circ}\text{C}}{\text{1.86 $\, ^{\circ}$C$\cdot$kg$\cdot$mol}^{-1}} = \text{0.250 mol/kg}$

2. Calculate the moles of solute

$\begin{array}{rcl}b & = & \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\\text{moles of solute} & = & b \times {\text{kilograms of solvent}}\\n & = &\text{0.250 mol/kg} \times \text{1.00 kg}\\ & = & \text{0.250 mol}\\\end{array}$

3. Calculate the molecular mass

$\begin{array}{rcl}\text{Moles} & = &\dfrac{\text{mass}}{\text{molar mass}}\\\\\text{0.250 mol} & = & \dfrac{\text{98.0 g}}{MM}\\\\MM & = & \dfrac{\text{98.0 g }}{\text{0.250 mol}}\\\\& = &\textbf{392 g/mol}\\\end{array}\\\text{The molecular mass of the solute is $\large \boxed{\textbf{392 u}}$}$

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4 years ago

When being transferred from one container to another, liquids will

RoseWind [281]

A. I’m not positive but I’m pretty sure

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3 years ago

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