Depression in freezing point (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) =
![K_{f}](https://tex.z-dn.net/?f=%20K_%7Bf%7D%20)
×m×i,
where,
![K_{f}](https://tex.z-dn.net/?f=%20K_%7Bf%7D%20)
= cryoscopic constant =
![1.86^{0} C/m](https://tex.z-dn.net/?f=%201.86%5E%7B0%7D%20C%2Fm)
,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For
![NaNO_{3}](https://tex.z-dn.net/?f=%20NaNO_%7B3%7D%20)
)
Thus, (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) = 1.86 X 0.0085 X 2 =
![0.03162^{0}C](https://tex.z-dn.net/?f=%200.03162%5E%7B0%7DC%20)
Now, (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) =
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
- T
Here, T = freezing point of solution
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
= freezing point of solvent =
![0^{0}C](https://tex.z-dn.net/?f=%200%5E%7B0%7DC%20)
Thus, T =
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
- (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) = -
Answer:
the final product is called a product
Explanation:
Answer:
The correct option is: a. degrees Celsius
Explanation:
The anion gap is the difference in the cations and anions in plasma, serum or urine, calculated from medical lab test results. It can be calculated by measuring the concentration of the anions or cations, which are expressed in millimoles/litre (mmol/L) or milliequivalents/liter (mEq/L).
The temperature in this test is expressed in degrees Celsius (°C).
Answer:
½O 2 + 2e - + H 2O → 2OH.
Explanation:
Redox reactions - Higher
In terms of electrons:
oxidation is loss of electrons
reduction is gain of electrons
Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:
iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-
oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-
iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-
<span>
Correct Answer:
Option 3 i.e. 30 g of KI dissolved in 100 g of water.
Reason:
Depression in freezing point is a
colligative property and it is directly proportional to molality of solution.
Molality of solution is mathematically expressed as,
Molality = </span>
![\frac{\text{Number of moles}}{\text{Weight of solvent (Kg)}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Ctext%7BNumber%20of%20moles%7D%7D%7B%5Ctext%7BWeight%20of%20solvent%20%28Kg%29%7D%7D%20)
<span>
In case of
option 1 and 2, molality of solution is
0.602 m. For
option 3, molality of solution is
1.807 m, while in case of
option 4, molality of solution is
1.205 m.
<u><em>Thus, second solution (option 2) has highest concentration (in terms of molality). Hence, it will have lowest freezing point</em></u></span>