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mylen [45]
3 years ago
7

g, Assuming the precipitate is totally insoluble in water, which aqueous ions will be present in the solution (collected in the

beaker) after the equivalence point (after the limiting reagent is used up)? Question 4 options: 1) Cl1- (aq) 2) Na1+ (aq) 3) OH1- (aq) 4) Cu2+ (aq)
Chemistry
1 answer:
Allushta [10]3 years ago
3 0

Answer:

Cl⁻, Na⁺, OH⁻

Explanation:

The titration is:

CuCl₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaCl(aq)

In solution, before the reaction, the ions are Cu²⁺ and Cl⁻. The addition of NaOH (Na⁺ + OH⁻) produce the precipitation of Cu²⁺ forming Cu(OH)₂(s). When you reach the equivalence point, there is no Cu²⁺ because precipitates completely. All OH⁻ ions reacts when are added but when Cu²⁺ is finished, excess OH⁻ ions still in solution helping to detect the equivalence point.

Thus, ions present after the equivalence point are:<em> Cl⁻, Na⁺</em> (Don't react, spectator ions), and <em>OH⁻</em>.

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P + O2 → P4O10 balance the equation
poizon [28]
4P + 502 -> P4O10 this is the answer
5 0
2 years ago
Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
MrRissso [65]

Answer:

6,97x10⁻³ gallons

Explanation:

pH is defined as:

pH = -log [H⁺]

Thus, you need to have, in the end:

10⁻⁷ = [H⁺]

And you have, in the first:

10^{-9,33} = [H⁺]

The volume of swimming pool is:

700'000 galllons ×\frac{3,78541 L}{1 gallon} = 2649787 L

Thus, the moles of H⁺ in the first and in the end are:

First:

10^{-9,33}mol/L × 2649787L = 1,24x10⁻³ moles

End:

10^{-7}mol/L × 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

0,26376moles*\frac{1L}{10moles}* \frac{1gallon}{3,78541L} =

<em>6,97x10⁻³ gallons</em>

<em></em>

I hope it helps!

7 0
3 years ago
What is meant by localised orbitals? Explain.
Anni [7]
Localized molecular orbitals are molecular orbitals which are concentrated in a limited spatial region of a molecule, for example a specific bond or a lone lake on a specific atom.
5 0
3 years ago
Turn on Write equation. What you see is an equation that shows the original uranium atom on the left. The boxes on the right rep
My name is Ann [436]

Answer:

Uranium-238 undergoes alpha decay to form Thorium-234 as daughter product.

Explanation:

Alpha decay is indicative of loss of the equivalents of a helium particle emission. The reaction equation for this reaction is shown below:

_{92} ^{238} U_{}→ _{90} ^{234} Th_{} + _{2} ^{4} He_{}

I hope this explanation is clear and explanatory.

6 0
3 years ago
The freezing point of a substance is -20°C. Its boiling point is 120°C.
Tasya [4]

Answer:

a. liquid

b. solid

c. gas, (should be at it's boiling point)

Explanation: If the normal melting point of a substance is below room temperature, the substance is a liquid at room temperature. Benzene melts at 6°C and boils at 80°C; it is a liquid at room temperature. If both the normal melting point and the normal boiling point are above room temperature, the substance is a solid.

if you need an explanation to each lmk

8 0
3 years ago
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