Answer:
Q = -18118.5KJ
W = -18118.5KJ
∆U = 0
∆H = 0
∆S = -60.80KJ/KgK
Explanation:
W = RTln(P1/P2)
P1 = 1bar = 100KN/m^2, P2 = 1500bar = 1500×100 = 150000KN/m^2, T = 23°C = 23 + 273K = 298K
W = 8.314×298ln(100/150000) = 8.314×298×-7.313 = -18118.5KJ ( work is negative because the isothermal process involves compression)
∆U = Cv(T2 - T1)
For an isothermal process, temperature is constant, so T2 = T1
∆U = Cv(T1 - T1) = Cv × 0 = 0
Q = ∆U + W = 0 + (-18118.5) = 0 - 18118.5 = -18118.5KJ
∆H = Cp(T2 - T1)
T2 = T1
∆H = Cp(T1 - T1) = Cp × 0 = 0
∆S = Q/T
Mass of water = 1kg
Heat transferred (Q) per kilogram of water = -18118.5KJ/Kg
∆S = (-18118.5KJ/Kg)/298K = -60.80KJ/KgK
1.95 or 2 is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.
The correct answer is option b
Explanation:
Data given:
mass of KN
= 45.3 grams
volume = 0.225 litre
molarity =?
atomic mass of KNO3 = 101 grams/mole
molarity is calculated by using the formula:
molarity = 
first the number of moles present in the given mass is calculated as:
number of moles = 
number of moles = 
0.44 moles of KNO3
Putting the values in the equation of molarity:
molarity = 
molarity = 1.95
It can be taken as 2.
The molarity of the potassium nitrate solution is 2.
3 because of the thing it’s trying to say
The rate of reaction would increase because as pressure increases the molecules are more likely to bump into each other leading to a more likely hood of the molecules colliding properly to react leading to an increase in the reaction rate of the substance.
I want to say physical change? i’m not quite sure, i hope this helps tho!
