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Flura [38]
3 years ago
9

If density is calculated by mass divided by volume and the mass increases, what would happen to the density of an object?

Chemistry
1 answer:
ZanzabumX [31]3 years ago
8 0
It would increase becuase it wouldn’t make sense if it decreased
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When 92.0 g of ethanol (c2h5oh are vaporized at its boiling point of 78.3°c, it requires 78.6 kj of energy. what is the approxim
Juli2301 [7.4K]

The solution would be like this for this specific problem:

<span>(78.6 kJ) / (92.0 g / (46.0684 g C2H5OH/mol)) = 39.4 kJ/mol </span>

<span>39.3 </span>

So the approximate molar heat of vaporization of ethanol in kJ/mol is 39.3.

I hope this answers your question.

7 0
3 years ago
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What’s the equation to solid calcium oxide reacts with hydrochloric acid to form a solution of calcium chloride and water as it’
meriva

Answer: CaO + 2HCl —> CaCl2 + H2O

Explanation:

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. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the
Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

\frac{P}{T}=k

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

\frac{P1}{T1} =\frac{P2}{T2}

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

  • P1= 0.450 atm
  • T1= 20 C= 293.15 K (being 0 C= 273.15 K)
  • P2=0.750 atm
  • T2= ?

Replacing:

\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}

Solving:

T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }

T2=\frac{0.750 atm}{0.450 atm} *293.15K

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0
3 years ago
if an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 mm in front of the len
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I think the answer is 7mm but I'm not sure.

Have a great day!
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