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3 years ago

WILL GIVE BRAINLIEST!!! Determine which of the values below are part of the solution set of the inequality

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

Answer:

Inequality Form:

x > 2

Interval Notation:

( 2 , ∞ )

Hope this helps :)

<em>-ilovejiminssi♡</em>

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TRUE OR FALSE GEOMETRY HONORS

nalin [4]

Answer:

I believe it is true

Step-by-step explanation:

A line never stops (extends infinitely in opposite directions)

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adelina 88 [10]

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Step-by-step explanation:

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3 years ago

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PLEASE HELP ME! Last question, and I'm stuck!

svetoff [14.1K]

The expression should be (2/h)x(k+8).

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3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

Cassie's broker charges her a commission of $4.25 for every ten shares of stock bought or sold. Cassie buys 92 shares of Hyren A

olya-2409 [2.1K]

Answer:

2,850

Step-by-step explanation:

4.25 x 9 = 38.25

4.25 x 13 = 55.25

4.25 x 12 = 51

13.70 x 92 = 1260.4

3.28 x 130 = 426.4

8.06 x 126 = 1015.56

all totals would equal 2,846.86, which to the nearest would be $2,850

4 0

3 years ago