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QveST [7]
3 years ago
15

Which linear function has the same slope as the one that is represented by the table?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

A linear function is one whose algebraic expression is of the type y= mx... For this, we are going to build its table of values, but we must not forget that it's.. the line is more inclined the greater the absolute value of the pending.

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frez [133]
The answer is C.
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7 0
2 years ago
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Sorting an excel table
Lana71 [14]

Sort data in a table

Select a cell within the data.

Select Home > Sort & Filter. Or, select Data > Sort.

Select an option: Sort A to Z - sorts the selected column in an ascending order. Sort Z to A - sorts the selected column in a descending order. Custom Sort - sorts data in multiple columns by applying different sort criteria.

6 0
3 years ago
Help!!!!!!!!!!!!!!!!
valkas [14]
Under box 36x + 9, Drag the following:

A.) 9(4x + 1)
D.) (9 . 4x) + (9 . 1)

Under box 9(4x - 1), Drag the following:
B.) (3 . 12x) - (3 . 3)
C.) 36x - 9

Under box (4 . 9x) + (4 . 2), Drag the following:
E.) 4(9x + 2)
F.) 36x + 8

Hope this helps!
5 0
3 years ago
How to solve this pythagoras theorem
My name is Ann [436]

Answer:

see explanation

Step-by-step explanation:

The hypotenuse is the longest side thus is (4x + 1)

The legs are 2x and (4x - 1)

Using Pythagoras' theorem, then

(4x + 1)² = (2x)² + (4x - 1)² ← expanding factors

16x² + 8x + 1 = 4x²  + 16x² - 8x + 1 , that is

16x² + 8x + 1 = 20x² - 8x + 1 ( subtract 20x² - 8x + 1 from both sides )

- 4x² + 16x = 0 ( multiply through by - 1 )

4x² - 16x = 0 ← factor out 4x from each term

4x(x - 4) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x - 4 = 0 ⇒ x = 4

Now x > 0, thus x = 4

2x = 2(4) = 8

4x - 1 = 4(4) - 1 = 16 - 1 = 15

4x + 1 = 4(4) + 1 = 16 + 1 = 17

Thus

perimeter = 8 + 15 + 17 = 40 cm

3 0
3 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
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