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exis [7]
3 years ago
14

Unrestrained growth of cells in a petri dish can be extremely rapid with a single cell growing into a number of cells given by t

he formula and parentheses T parentheses equals eight to the tea after T hours enter the formula for the number of cells in the petri dish on a culture started with 20 isolated sauce
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0
Deeeeeeeeeeeeeeeeeeeeeeeeez nuts
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Which angles are alternate exterior angles?
omeli [17]
A. 2 and 8
It’s the pair of angles on the outer side of each of those two lines but on opposite of the transversal.
4 0
3 years ago
What is an equation of the line that passes through the points (4, 4) and (8, 1)?
geniusboy [140]

Answer: y = -3/4x + 7

Step-by-step explanation:

first find slope:

y2-y1 / x2 - x1

1-4 / 8-4

-3/4

now just plug the slope (m) into the equation of a line using one of the points to find the y intercept

ill use (8,1)

1 = (-3/4)(8) + b

now solve :)

1 = -6 + b

7 = b

so now plug in the slope and the y intercept into the slope intercept form to find the equation of the line

y = -3/4x + 7

3 0
3 years ago
Need help plz I'll give you brainlest it isn’t multiple choice plz help it geometry
Savatey [412]
B is 747.7 ..................
5 0
2 years ago
Apply The Remainder Theorem, Fundamental Theorem, Rational Root Theorem, Descartes Rule, and Factor Theorem to find the remainde
Over [174]

9514 1404 393

Answer:

  possible rational roots: ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12}

  actual roots: -1, (2 ±4i√2)/3

  no turning points; no local extrema

  end behavior is same-sign as x-value end-behavior

Step-by-step explanation:

The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.

The Rational Root Theorem tells us any rational roots will be of the form ...

  ±{factor of 12}/{factor of 3} = ±{1, 2, 3, 4, 6, 12}/{1, 3}

  = ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12} . . . possible rational roots

Descartes' Rule of Signs tells us the two sign changes mean there will be 0 or 2 positive real roots. Changing signs on the odd-degree terms makes the sign-change count go to 1, so we know there is one negative real root.

The y-intercept is 12. The sum of all coefficients is 22, so f(1) > f(0) and there are no positive real roots in the interval [0, 1]. Synthetic division by x-1 shows the remainder is 22 (which we knew) and all the quotient coefficients are all positive. This means x=0 is an upper bound on the real roots.

The sum of odd-degree coefficients is 3+8=11, equal to the sum of even-degree coefficients, -1+12=11. This means that -1 is a real root. Synthetic division by x+1 shows the remainder is zero (which we knew) and the quotient coefficients alternate signs. This means x=-1 is a lower bound on real roots. The quotient of 3x^2 -4x +12 is a quadratic factor of f(x):

  f(x) = (x +1)(3x^2 -4x +12)

The complex roots of the quadratic can be found using the quadratic formula:

  x = (-(-4) ±√((-4)^2 -4(3)(12)))/(2(3)) = (4 ± √-128)/6

  x = (2 ± 4i√2)/3 . . . . complex roots

__

The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.

4 0
3 years ago
I Need help please I don’t understand this
Otrada [13]

Remember that parentheses come first. Follow PEMDAS

4 0
3 years ago
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