The line will flip across the y-axis.
The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
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As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
Answer:
5/3
Step-by-step explanation:
Trigonometric ratio
Cot θ = Adjacent side/Opposite side
It is given that,
Cot θ = 4/3
Adjacent side = 4
Opposite side = 3
Csc θ = Hypotenuse/Opposite side
To find the Hypotenuse
Hypotenuse² = Opposite side² + Adjacent side ² = 3²+ 4²
Hypotenuse = √(3²+ 4²) = 5
To find Csc θ
Csc θ = Hypotenuse/Opposite side = 5/3
Answer:
x=24cm
y=20,78cm
Step-by-step explanation:
sen(30)=
-> x*sen(30)=12 -> x=
= 24cm
cos(30)=y/x -> cos(30)= y/24 -> y=24*cos(30)= 20,78cm
For factorisation it is necessary that you multiply the last and first values
Here we can see : we require 27a^2
SO if we multiply the answer should be 27 and if we add the answer should be 28 ....here goes !!
a^2 + 28a + 27
a^2 + 27a + 1a + 27
Here we can see : I we multiply 27 and 1 the answer will be 27a^2 but if we add 27 and 1 as shown then answer will be 28a:
a ( a + 27 ) + 1 ( a + 27 )
( a + 1 ) × (a + 27 )
HOPE IT HELPED!!
