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BabaBlast [244]
3 years ago
9

Write an equation that gives the overall equilibrium constant of 2Fe2O3+6C+3O2=4Fe+6CO2

Chemistry
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

K = [Fe]4×[CO2] / [Fe2O3]2 × [C]6 × [O2]3

Explanation:

the over all reaction is

2Fe2O3(s) + 6C(s) + 3O2(g) ---> 4Fe(I) + 6CO2 (g)

So equilibrium constant equals, product concentration/ reactant concentration.

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When electrons add into valence shell of neutral elements, the element assumes a negative oxidation state. With this, the number of electrons having (-) charges will be larger than the number of protons having positive (+) charges. As a result, the extra electrons repel one another (i.e., like charges repel) and a larger radius is the result.  

In contrast, when cations are formed, electrons are removed from the valence level (oxidation) producing an element having a greater number of protons than electrons. The larger number of protons will function to attract the electron cloud with a greater force that results in a contraction of atomic radius and a smaller spherical volume than the neutral unionized element.    

To visualize, see attached chart that shows atomic and ionic radii before and after ionization of the elements.  

Download pdf
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