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Pavel [41]
4 years ago
8

Identify the type of reaction represented by each equation.

Chemistry
2 answers:
MrRissso [65]4 years ago
7 0

Answer : Equation A represents a combination reaction, and equation B represents a combustion reaction.

Explanation :

  • Equation A : H_2+Cl_2\rightarrow 2HCl

In this reaction, hydrogen react with the chlorine to form a single product as hydrogen chloride. So, this reaction is a combination reaction.

Combination reaction : It is a type of chemical reaction in which two or more  reactants combine to produce a single product.

  • Equation B : CH_4+2O_2\rightarrow CO_2+2H_2O

In this reaction, methane is a hydrocarbon react with the oxygen to give carbon dioxide and water as a product. So, this reaction is a combustion reaction.

Combustion reaction : A type of chemical reaction where a hydrocarbon molecule react with the oxygen to produces carbon dioxide and water as a product.

Hence, the Equation A represents a combination reaction, and equation B represents a combustion reaction.

My name is Ann [436]4 years ago
7 0

Equation A represents a combination reaction, and equation B represents a combustion reaction. Hope this helps!

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andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

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3 years ago
How many moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torr?
andre [41]

2.2311 moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torrs.

<h3>What is an ideal gas?</h3>

An Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Assuming the gas is ideal, we can solve this problem by using the following equation:

PV = nRT

Where:

P = 825 torr ⇒ 825 / 760 = 1.08 atm

V = 50 L

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We input the data:

1.08 atm x 50 L = n x 0.082 atm·L·mol⁻¹·K⁻¹ x 295.16 K

And solve for n:

24.20312

n = 2.2311 mol

Hence, 2.2311 moles of gas are there in a 50. 0 L container at 22. 0 °c and 825 torrs.

Learn more about ideal gas here:

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