What kind of attraction pulls electrons close to the atomic nucleus?
1 answer:
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Answer: The actual free-energy change for the reaction -8.64 kJ/mol.
Explanation:
The given reaction is as follows.
Fructose 1,6-bisphosphate Glyceraldehyde 3-phosphate + DHAP
For the given reaction, is 23.8 kJ/mol.
As we know that,
Here, R = 8.314 J/mol K, T =
= (37 + 273) K
= 310.15 K
Fructose 1,6-bisphosphate = M
Glyceraldehyde 3-phosphate = M
DHAP = M
Expression for reaction quotient of this reaction is as follows.
Reaction quotient =
Q =
=
Now, we will calculate the value of as follows.
=
= -8647.73 J/mol
= -8.64 kJ/mol
Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.