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belka [17]
3 years ago
5

Can anyone help me with my homework

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

1: (0,3)

2: (-4,-2)

3: (-1,-5)

4: (4,0)

Step-by-step explanation:

Mandarinka [93]3 years ago
4 0
A F G I

i worked it out
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Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
What is median height of 72, 75, 78, 72, and 73?
sleet_krkn [62]
The median height is the one in the middle when placed in numerical order. Which in this case, it is 73. (the bolded numbers are those that are being crossed out)

72, 72, 73, 75, 78
72, 72, 73, 75, <span>78
</span>72, 72, 73, 75, 78

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maria [59]
For example, y = k/x; when x = 3 => k = 3y; when y = 9 => k = 27  and x = 27/9 = 3;
The answer is 3!
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What is x+2x=100<br><br> what is x?
Vesnalui [34]

I am not sure about the answer but all you have to think about is what is 100 divided by 3

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