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Alexandra [31]
2 years ago
7

April wants to paint three walls of her bedroom. The walls are each 90 square feet. Paint is only sold in whole quarts, and each

quart of paint will cover 100 square feet. How many quarts of paint must she purchase to have sufficient paint for this job?
Mathematics
1 answer:
Ganezh [65]2 years ago
3 0

Answer:

she should buy 3 quarts and keep the remainder which can possibly cover 30 square feet.

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Please help i mark brainiliest​
7nadin3 [17]

Answer:

2: 15

3: 20

for the second chart

0: -2

2: 8

4: 18

6: 28

I hope this helped :))

i hope this is correct '~'

6 0
2 years ago
Patricia owned so many posters that she decided to sell 64 of them to her friends. After selling the posters, she still had 176
ValentinkaMS [17]

Answer:

p - 64 = 176

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the value of x. 50 points
notka56 [123]
The answer is 138
Because the angle is 180 and what I did was 2 x 21 = 42 and I did 180-42 equals to 138
7 0
1 year ago
Read 2 more answers
I need help on question 2 i need the simplified answer and the restrictions
Anastaziya [24]

Answer:

x cannot be 5 or -3.

\frac{x+5}{x+3}

Step-by-step explanation:

The restrictions for a fraction is that the bottom cannot be 0.

So if we find when the bottom is 0 we have found the values that x cannot be.

Let's solve x^2-2x-15=0.

Since the coefficient of x^2 is 1 all we have to do is find two numbers whose product is -15 and whose sum is -2.

Those numbers are -5 and 3 since (-5)(3)=-15 and (-5)+(3)=-2.

So the factored form of the equation is:

(x-5)(x+3)=0

This means either x-5=0 or x+3=0.

We do have to solve both.

x-5=0 can be solved by adding 5 on both sides.

x-5+5=0+5

x+0=0+5

x=5

x+3=0 can be solved by subtracting 3 on both sides.

x+3-3=0-3

x+0=0-3

x=-3

So x can be any number except x=5 or x=-3.

We already factored the bottom as (x-5)(x+3).

The top is a difference of squares, x^2-a^2,

which can be factored as (x-a)(x+a).

So the top factors as (x-5)(x+5).

The fraction can then be written as:

\frac{x^2-25}{x^2-2x-15}=\frac{(x-5)(x+5)}{(x-5)(x+3)}

This can further simplified assuming x is not 5 we can write it as \frac{x+5}{x+3}.  I canceled the common factor of (x-5).

5 0
3 years ago
a rectangle box has length 12 inches, width 15 inches, and a height of 17 inches. Find the angle between the diagonal of the box
ANTONII [103]

Answer:

0.7246 radians

Step-by-step explanation:

According to the Question,

Given that, a rectangle box has length 12 inches, width 15 inches, and a height of 17 inches

  • The length of the base diagonal (d) can be found using the Pythagorean theorem on length and width:

d = √{ (12)² +(15)² }  = √(144+225) = √369inches

  • The tangent of the angle is the ratio of the height of the box to this length

 Tan∅ = 17/√369

Taking the Tan^{-1} , we have

∅ = Tan^{-1}(17/√369) ≈ 0.7246 radians

4 0
3 years ago
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