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GenaCL600 [577]
3 years ago
10

Some ordered pairs for a linear

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

y=3x-2

Step-by-step explanation:

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An entrepreneur faces many bureaucratic and legal hurdles when starting a new business. The World Bank collects information abou
slamgirl [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Rearranged data:

5, 5, 5, 5, 6, 7, 7, 7, 8, 12, 12, 13, 13, 15, 18, 18, 27, 28, 36, 48, 52, 60, 66, 94

Start time for Suriname = 694

Mean = ΣX / n

Mean = (567 + 694) / (24 + 1) = 1261 / 25 = 50.44

B.) median start Time for initial 24 values

0.5(n+1)th term

0.5(25) = 12.5th term

(13 + 13) / 2 = 13

C.) preferred measure of center for the distribution will be the median as it shapes well in the middle of the distribution. The mean is overestimated

d) Compute the quartiles (Q1, Q2, Q3), and find the IQR for these data. Are there outliers in the time to start a business data set? If so, identify and name any outliers.

Using calculator :

Lower quartile Q1 --> 7

Median Q2 --> 13

Upper quartile Q3 --> 42

IQR = (Q3 - Q1) = 42 - 7 = 35

OUTLIER:

Lower bound : Q1 - 1.5(IQR) ; 7 - 1.5(35) = - 45.5

Upper bound : Q3 + 1.5(IQR) = 42 + 1.5(35) = 94.5

Outlier : values below - 45.5 and above 94.5

Hence, Surimanes start time is the only Outlier.

e)

Standard deviation for 24 countries :

Standard deviation = sqrt[Σ(X - mean)^2 / (N - 1)]

Usibg calculator :

Standard deviation for the 24 countries is 23.83

f)

Standard deviation

5 0
3 years ago
A magician has four playing cards in random order in his hand ( 3 4 5 and 6)
VladimirAG [237]

4 6 5 3 (from magician perspective)

3 5 6 4 (viewer perspective)


Detail:


From user perspective:

3 5 6 4 => 5 6 4 3 => 6 5 4 3


For magician perspective

3 4 5 6 (ascending order as)

5 0
4 years ago
Read 2 more answers
*WILL MARK BRAINLIEST* 15 POINTS<br> Match each word to its correct definition:
IgorC [24]

Answer:

2  

3

1

4

Step-by-step explanation:

Angles that add up to 90 are Complementary angles.

Two angles that have a common vertex and a common side but do not overlap are Adjacent angles.

Angles that are opposite each other and have the same measurment are vertical angles.

Angles that add up to 180 are Supplementary angles.

Hope this helps!! :D

7 0
3 years ago
Read 2 more answers
School is making digital backups of old reels of film in its library archives the table shown approximate run Times of the films
Gemiola [76]

One technique that you can apply when solving such a problem is trial and error. We try to use each equation to prove that a given value of <em>x</em> on the table given will correspond to the value of <em>y</em> on the table.

a) Let's try to put x = 3 for the first equation and we must get an answer equal to 2.25.

y=7.72(3)-29.02=-5.86_{}

Since the value of <em>y</em> is not equal to 2.25 and the deviation is too large. this equation is not a good model,

b) We put x = 3 on the second equation and solve for <em>y</em>

y=-7.52(3)^2+0.19(3)+3.26=-63.85

Since the value of <em>y</em> is not equal to 2.25 and the deviation is too large. this equation is not a good model,

c) We put <em>x</em> = 3 on the third equation and solve for <em>y,</em>

y=0.4(3)^2+0.79(3)-4.93=1.04

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of <em>x</em>. If x = 5, we get

y=0.4(5)^2+0.79(5)-4.93=9.02

which has a slight deviation on the given value of <em>y</em> on the table for <em>x</em> = 5. let's try for <em>x</em> = 7. We have

y=0.4(7)^2+0.79(7)-4.93=20.2

and the answer has a small deviation compared to the actual value given. The other values of <em>x</em> can again be put on the equation and check their corresponding value of <em>y</em>, and the resulting values are as follows

\begin{gathered} y=0.4(8)^2+0.79(8)-4.93=26.99 \\ y=0.4(12)^2+0.79(12)-4.93=62.15 \\ y=0.4(14)^2+0.79(14)-4.93=84.53 \end{gathered}

And as you can see, the deviation of values from the table to calculated becomes smaller. Hence, this is the best model.

d) We put <em>x</em> = 3 on the third equation and solve for <em>y,</em>

y=4.19(1.02)^3=4.45_{}_{}

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of <em>x</em>. If x = 5, we get

y=4.19(1.02)^5=4.63

where the answer's deviation is too large compared to the value of <em>y</em> if x = 5 on the table given.

Based on the calculations used above, the best equation that can be a good model is equation 3.

5 0
1 year ago
Another one for yall
zavuch27 [327]

Answer:

domain (-2, infinity)

range(0,infinity)

5 0
3 years ago
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