Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
This can help you
a) since it is discrete we need to think about the sum thing
it it was continuous we would look at an integral thing
so I think if I remember correctly we need to find c such that
<span><span>∑<span>i=0</span>3</span>c(<span>x2</span>+4)=1
b) </span>
problem b is a similar setup
<span>1.perpendicular bisector.
2.midpoint.
3.perpendicular bisector.</span>
Answer:
CORRECT OPTION is (C) The flight will be late on one of the three days.
Step-by-step explanation:
The 7am flight from Dallas to Chicago is on time 75% of the time.
A spinner with four sections was created by Fran to simulate this scenario.
Since the 4 sections were equal, it means each section was 25% of the spinner.
3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.
This coincides with the 75% probability that the flight is on time on a given day.
In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.
Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:
- Shaded - Shaded - Unshaded
CORRECT OPTION is (C) The flight will be late on one of the three days.
Answer:
D
Step-by-step explanation:
D is more appropriate for distance formula because you are looking for the whole length between two points rather than the point in between the the two points such as in the other answers.