$\dfrac{2}{5}+p=\dfrac{4}{5}+\dfrac{3}{5}p\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}+5p=5\!\!\!\!\diagup^1\cdot\dfrac{4}{5\!\!\!\!\diagup_1}+5\!\!\!\!\diagup^1\cdot\dfrac{3}{5\!\!\!\!\diagup_1}p\\\\2+5p=4+3p\qquad\text{subtract 2 from both sides}\\\\5p=2+3p\qquad\text{subtract 3p from both sides}\\\\2p=2\qquad\text{divide both sides by 2}\\\\p=1$

4 0

3 years ago

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Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train

CaHeK987 [17]

You can add the times together and calculate the speed over the full length, because both trains have the same speed
$speed=rate=\frac{distance}{time}\\
\frac{562.5}{3.5+4} = \frac{562.5}{7.5}=75 mph$

6 0

4 years ago

I need help and show work​

I need help and show work