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lisabon 2012 [21]

3 years ago

15

2/x-1=3/3x-3+1/6 Please solve for x

1 answer:

sweet [91]3 years ago

3 0

Answer:

1y

Step-by-step explanation:

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I think 8 are classical songs

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2 years ago

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Show me how to work the equation 30-f+8f=30

ELEN [110]

30-f+8f=30

30+7f=30

Move +30 to the right side. Sign changes from +30 to -30.

30-30+7f=30-30

7f=0

Divde by 7

7f/7=0/7

Cross out 7 and 7, divide by 7. Becomes 1*1*f=f

f=0

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ASAP HELP PLEASE! WILL GIVE BRAINLIEST

Mila [183]

Answer:

Least Value = 2
Median = 6
Greatest Value = 10
Third Quartile = 8
Range = 8 (10 - 2 = 8)
First Quartile = 5

Step-by-step explanation:

7 0

2 years ago

Find the quotient. 48j5k2 ÷ (-3j3k)

Sindrei [870]

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Step-by-step explanation:

3 0

3 years ago

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago