Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
12.
Step-by-step explanation:

Substitute this equation with a=3 and b=24:



Step-by-step explanation:
Make a point P that will be the vertex of the new angle.
From P, draw a ray PQ. ...
Place the compasses on point A, set to any convenient width.
Draw an arc across both sides of the angle, creating the points J and K as shown.
Hope this helps :)
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (4, 6)
Point (-2, -2)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute [DF]:

- Subtract:

- Exponents:

- Add:

- Evaluate:
